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DSSSB PGT Arithmetical & Numerical Ability Mastery Hub: Prac

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Q1Domain Verified
In the context of the given course, what is the primary characteristic that distinguishes a "perfect number" from a "deficient number"?
Perfect numbers have exactly two distinct prime factors, while deficient numbers have more than two.
Perfect numbers are divisible by all prime numbers up to their square root, while deficient numbers are not.
Perfect numbers have a sum of divisors (excluding the number itself) that is equal to the number, while deficient numbers have a sum of divisors less than the number.
Perfect numbers are always even, whereas deficient numbers can be either even or odd.
Q2Domain Verified
probes the fundamental definition of perfect and deficient numbers, a core concept in number theory discussed in the course. Option A accurately defines both terms: a perfect number's proper divisors sum to the number itself (e.g., 6 = 1+2+3), and a deficient number's proper divisors sum to less than the number (e.g., 8: 1+2+4 = 7 < 8). Option B is incorrect because while the first few perfect numbers are even, it's an open conjecture whether odd perfect numbers exist. Option C introduces an irrelevant criterion; divisibility by primes up to the square root is related to primality testing, not the definition of perfect or deficient numbers. Option D is incorrect; perfect numbers can have varying numbers of prime factors (e.g., 6 = 2*3 has two, but 28 = 2^2 * 7 has two prime factors but three distinct divisors including the number itself. The definition hinges on the sum of divisors, not the count of prime factors. Question: Consider the set of integers $Z$. If $a \equiv b \pmod{m}$ and $a \equiv c \pmod{m}$, which of the following statements is a direct consequence of the properties of modular arithmetic as taught in the course?
$b \equiv c \pmod{m}$ and $m \equiv 0 \pmod{b-c}$.
$b \equiv c \pmod{m}$ and $m$ is a divisor of $b-c$.
All of the above.
$b \equiv c \pmod{m}$ and $b-c$ is a multiple of $m$.
Q3Domain Verified
tests the understanding of the transitive property of modular congruence and its implications. If $a \equiv b \pmod{m}$, it means $a-b = km$ for some integer $k$. If $a \equiv c \pmod{m}$, it means $a-c = lm$ for some integer $l$. Subtracting these equations, $(a-b) - (a-c) = km - lm$, which simplifies to $c-b = (k-l)m$. This directly implies $b-c = -(k-l)m$, meaning $b-c$ is a multiple of $m$. Therefore, $b \equiv c \pmod{m}$. Option A is partially correct in stating $b \equiv c \pmod{m}$, but the second part, $m \equiv 0 \pmod{b-c}$, is a restatement of the same relationship and not a distinct consequence. Option B correctly states $b \equiv c \pmod{m}$ and $b-c$ is a multiple of $m$. Option C correctly states $b \equiv c \pmod{m}$ and $m$ is a divisor of $b-c$, which is the definition of $b \equiv c \pmod{m}$. Since Options B and C are both valid and D encompasses all correct implications derived from the transitive property and definition of modular arithmetic, D is the most comprehensive and correct answer. Question: In the advanced divisibility rules discussed in the course, what is the underlying principle that allows for determining the divisibility of a number by 7 using alternating sums of blocks of three digits?
The principle of digit manipulation, where the sum of digits relates to divisibility by 7.
The principle of modular arithmetic, specifically that $1000 \equiv -1 \pmod{7}$.
The principle of geometric progression, where the blocks of digits form a geometric series.
The principle of prime factorization, where 7 is a prime factor of the alternating sum.

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